First, let’s write the given sets in the list form:
A = { x | 3x − 1 = 2}
3x − 1 = 2
∴ 3x = 2 + 1
∴ 3x = 3
∴ x = \(\displaystyle \frac{3}{3}\)
∴ x = 1
∴ A = {1} ... (i)
And B = { x | x is a natural number but x is neither prime nor composite.}
∴ x = 1
∴ B = {1} ... (ii)
And C = { x | x ∈ N, x < 2}
∴ x = 1
∴ C = {1} ... (iii)
From (i), (ii), and (iii), we have:
Sets A, B, and C have exactly the same element(s).
∴ A = B = C
∴ Sets A, B, and C are equal sets.
First, let's write the given sets in the list form:
A = {2} ... (Since 2 is the only even prime number) ... (i)
B = {x | 7x − 1 = 13}
7x − 1 = 13
∴ 7x = 13 + 1
∴ 7x = 14
∴ x = \(\displaystyle \frac{14}{7}\)
∴ x = 2
∴ B = {2} ... (ii)
From (i) and (ii),
Sets A and B have exactly the same element(s).
∴ A = B
∴ Sets A and B are equal sets.
There is no natural number which is less than 0.
∴ A is an empty set.
B = {0}
Thus, B is a set which contains an element 0.
∴ B is not an empty set.
5x − 2 = 0
∴ 5x = 2
∴ x = \(\displaystyle \frac{2}{5}\)
But, x ∈ N
and \(\displaystyle \frac{2}{5}\) is not a natural number.
∴ C is an empty set.
A = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
∴ A is a set which contains 10 elements.
∴ A is a finite set.
B = { − 2, − 3, − 4, − 5, ... }
Thus, B is a set which contains infinitely many elements.
∴ B is an infinite set.
C = {students of class 9 from your school}
Thus, C is a set which contains a definite number of elements.
∴ C is a finite set.
This is a set which contains a definite number of elements.
∴ This is a finite set.
This is a set which contains a definite number of elements.
∴ This is a finite set.
W = { 0, 1, 2, 3, ... }
Thus, W is a set which contains infinitely many elements.
∴ W is an infinite set.
This is an infinite set.
This page was last modified on
06 April 2026 at 14:01